Question

A body of mass 20 kg moving with speed of 10ms on a horizontal smooth surface collides with massless spring of spring constant 5N/m. If the mass stols after collision, distance of compression of the spring will be?

Answer 1

That's a simple mechanics assuming ideal conditions the forces the box directly comes from 20 m/s to 0 m/s which is considered as an ideal thus using Newton sir's second law we get

Ma=kx

200/5 = K

THUS 40 kgm/s^2/N/m

Answer 2

Answer:

CORRECT ANSWER : 20M

HOPE IT HELPS