Question

A body of mass 200 g initially at rest travels a distance of 100 m in 5 s with a constant
acceleration. Calculate
a. acceleration
b.
final velocity
C. final momentum at the end of 5 s​

Answer 1

Explanation:

m = 200g

convert it into kg then,

m = 0.2 kg

initial velocity vi = 0

distance d = 100 m

time t = 5sec

To find:

a = ?

vf = ?

p = ?

Calculations

acceleration has the formula d/t = 100/5 = 20 ms^-2

By using newtons first equation of motion

vf = vi + at

by putting values vf = 0 + 20(5) = vf = 100

Final momentum pf = mv = 0.2(100) = 20 N·s

Answer 2

Answer:

4m/s^2,20m/s,4 kg.m/s

Explanation:

Mass(m)=200g

Initial velocity(u)=0m/s(body is initially at rest)

Distance(d)=100m

Time(t)=5s

Now,

Velocity(v)=displacement/time

             = 100/5=20

Therefore, final velocity(v)=20m/s as initial velocity(u)=0m/s

Now,

Acceleration(a)=(v-u)/t=20-0/5=4

Therefore, a=4m/s^2

Momentum=m*v=0.2(si system conversion of 200g)*20(velocity is constant and body doesnt come at rest)=4 kg.m/s