a body of mass 200 gram is thrown in upward direction with velocity 40 m per second which takes the two seconds calculate ke of same body
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Equations in use for this question are
v= u- gt
v final velocity u initial velocity g accln due to gravity and t time
-ve symbol because speed reduces when thrown upward due to gravity.
then we will use
KE = 1/2 m v2
From 1st eqn we get v= 19 m/ s
and from 2nd eqn we will get
KE= 36.1 J
Let me know if i am wrong somewhere
v= u- gt
v final velocity u initial velocity g accln due to gravity and t time
-ve symbol because speed reduces when thrown upward due to gravity.
then we will use
KE = 1/2 m v2
From 1st eqn we get v= 19 m/ s
and from 2nd eqn we will get
KE= 36.1 J
Let me know if i am wrong somewhere
saku2003:
How we get num from 1st and 2nd eqn
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