Question

A body of mass 200 N is placed in water. It weighs 150 N in
water. The volume of the body is

Answer 1

Given that,

Weight of body in air = 100 N

Buoyant force = Weight of liquid displaced

Volume of water displaced = 400 cc

2

Density of water = 1g/cm3

In this case,

ρ=

V

m

m=ρ×V

m=1×400

m=400g

We know that,

The weight of water displaced is

W=m×g

W=

5

2

×9.8

W=3.92N

Now, weight of the object in water

W=100−3.92

W=96.08

W=96N

Hence, the weight of object in water is 96 N