Question

A body of mass 200g performs linear SHM with period 2π sec.what is the force constant? ​

Answer 1

Given:

A body of mass 200g performs linear SHM with period 2π seconds.

To find:

Force constant?

Calculation:

The expression of time period of a particle performing Simple Harmonic Motion (SHM) is as follows:

$T = 2\pi \sqrt{ \dfrac{m}{k} }$

$\implies 2\pi= 2\pi \sqrt{ \dfrac{0.2}{k} }$

$\implies 1= \sqrt{ \dfrac{0.2}{k} }$

$\implies {1}^{2} = \dfrac{0.2}{k}$

$\implies k = 0.2 \: kg/ {s}^{2}$

So, force constant is 0.2 kg/s².