Question

a body of mass 200g requires 2000j of heat energy in order to raise its temperature from 35°c to 45°c. calculate the specific heat capacity of the body​

Answer 1

Answer:

1J/g°c

Explanation:

use,

Q=msT

m is mass of body,

Q is heat needed,

T is change in temperature,

s is specific heat capacity

Answer 2

The specific heat capacity of the body is $c=35.34 Jkg^{-1}K^{-1}$.

Explanation:

The expression for the heat energy in terms of mass and change in temperature is as follows;

$Q=mc\Delta T$

Here, Q is the heat energy, m is the mass and $\Delta T$ is the change in temperature.

It is given in the question that a body of mass 200 g requires 2000 j of heat energy in order to raise its temperature from 35°c to 45°c.

Convert mass from gram to kilogram.

1 kg = 1000 g

$m=\frac{200}{1000}$

m = 0.2 kg

Calculate the change in temperature.

$\Delta T= T_{f}-T_{i}$

Here, $T_{f}$ is the final temperature and $T_{i}$ is the initial temperature.

Put $T_{f}=45 C^{\circ}$ and $T_{i}=35 C^{\circ}$

$\Delta T=45 C^{\circ} -35 C^{\circ}$

$\Delta T=10 C^{\circ}$

Convert change in temperature from degree celsius to kelvin.

$\Delta T=10 + 273$

$\Delta T=283 K$

Calculate the specific heat capacity of the body by using the expression of heat energy.

$c=\frac{Q}{m\Delta T}$

Put $\Delta T=283 K$, m = 0.2 kg and Q= 2000 J.

$c=\frac{2000}{(0.2)(283)}$

$c=35.34 Jkg^{-1}K^{-1}$

Therefore, the specific heat capacity of the body is $c=35.34 Jkg^{-1}K^{-1}$.