Question

a body of mass 200kg is falling from a height 100m . Find its kinetic energy when it is 1/3 of the total height.

Answer 1

answer is 400000/3 J that is 133333.3J

Answer 2

1/3 of the total height = 33.33m
distance travelled by the body(h)= 66.66m
acceleration due to gravity(g)(assumption)=9.8m/s^2
initial velocity of the body(u)= 0m/s
calculating it's final velocity
by using the formula
${v }^{2} = {u}^{2} + 2gh$
v= 36.14 m/s
calculate the kinetic energy by usimg the formula
$kinetic \: energy = 1 \div 2m {v}^{2}$
mass(m)= 200kg v=36.14m/s
kinetic energy=130609.96 joule