a body of mass 20kg is dropped from a height of 100m.find its kinetic energy amd potential energy of 1st second, 2nd second and 3rd second
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T=1 sec
M=20kg
H=100m
g=10m/s2
V=u+gt
=0+10×1
=10 m/s
K.E.=1/2 MV2
=1/2 × 20×10^2
=10×100
=1000Joules
M=20kg
H=100m
g=10m/s2
V=u+gt
=0+10×1
=10 m/s
K.E.=1/2 MV2
=1/2 × 20×10^2
=10×100
=1000Joules
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