Question

A body of mass 20kg is initially at rest. A force of 10N is applied to the body. Find the velocity of the body after 10 seconds and the distance covered by it in ten seconds on the application of the force. ​

Answer 1

Explanation:

F=10N,m=20kg,t=10s

a=

m

F

=

20

10

=0.5m/s

2

v=u+at=0+0.5×10=5m/s

Change in momentum =m(v−u)=20(5−0)=100kgm/s