Physics, asked by basitmushtaq125, 1 month ago

A body of mass 20kg is kept at a height of 15m. Calculate the potential energy of the body.

Answers

Answered by Anonymous
14

Answer:

Given :-

  • A body of mass 20 kg is kept at a height of 15 m.

To Find :-

  • What is the potential energy of the body.

Formula Used :-

\clubsuit Potential Energy Formula :

\mapsto \sf\boxed{\bold{\pink{P.E =\: mgh}}}

where,

  • P.E = Potential Energy
  • m = Mass in (kg)
  • g = Acceleration due to gravity (9.8 m/)
  • h = Height in (m)

Solution :-

Given :

\bigstar\: \: \bf{Mass\: (m)=\: 20\: kg}

\bigstar\: \: \bf{Acceleration\: due\: to\: gravity\: (g) =\: 9.8\: m/s^2}

\bigstar\: \: \bf{Height\: (h) =\: 15\: m}

According to the question by using the formula we get,

\longrightarrow \bf P.E =\: mgh

\longrightarrow \sf P.E =\: (20)(9.8)(15)

\longrightarrow \sf P.E =\: 20 \times 9.8 \times 15

\longrightarrow \sf P.E =\: 196 \times 15

\longrightarrow \sf\bold{\red{ P.E =\: 2940\: J}}

{\small{\bold{\underline{\therefore\: The\: potential\: energy\: of\: the\: body\: is\: 2940\: J\: .}}}}

Answered by Anonymous
38

\huge\fcolorbox{lime}{black}{\color{lime}{Answer}}

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 \sf \red {potential\: Energy:-}

➳ɪᴛ ɪs ᴛʜᴇ ᴇɴᴇʀɢʏ ᴘᴏssᴇssᴇᴅ ʙʏ ᴀ ʙᴏᴅʏ ʙʏ ᴠɪʀᴛᴜᴇ ᴏғ ɪᴛs ᴘᴏsɪᴛɪᴏɴ ʀᴇʟᴀᴛɪᴠᴇ ᴛᴏ ᴏᴛʜᴇʀs, sᴛʀᴇssᴇs ᴡɪᴛʜɪɴ ɪᴛsᴇʟғ, ᴇʟᴇᴄᴛʀɪᴄ ᴄʜᴀʀɢᴇ, ᴀɴᴅ ᴏᴛʜᴇʀ ғᴀᴄᴛᴏʀs.

➳ ᴘᴏᴛᴇɴᴛɪᴀʟ ᴇɴᴇʀɢʏ ɪs ᴀ sᴄᴀʟᴀʀ ǫᴜᴀɴᴛɪᴛʏ ᴀɴᴅ ɪs ᴍᴇᴀsᴜʀᴇᴅ ɪɴ ᴊᴏᴜʟᴇs(J).

________________________

Ⓔⓧⓐⓜⓟⓛⓔⓢ:-

  1. ᴀ ʙᴏᴏᴋ ᴏɴ ᴀ ᴛᴀʙʟᴇ ʙᴇғᴏʀᴇ ɪᴛ ғᴀʟʟs.
  2. ᴀ ʏᴏ-ʏᴏ ʙᴇғᴏʀᴇ ɪᴛ ɪs ʀᴇʟᴇᴀsᴇᴅ.

________________________

Ⓕⓞⓡⓜⓤⓛⓐ:-

 \sf  {\fbox {P.E=mgh}}

________________________

Ⓦⓗⓔⓡⓔ,

➳ᴍ ɪs ᴛʜᴇ ᴍᴀss ᴏғ ᴛʜᴇ ʙᴏᴅʏ (ɪɴ ᴋɪʟᴏɢʀᴀᴍs)

➳ɢ ɪs ᴛʜᴇ ᴀᴄᴄᴇʟᴇʀᴀᴛɪᴏɴ ᴅᴜᴇ ᴛᴏ ɢʀᴀᴠɪᴛʏ

➳ɢ=  {9.8m/s^{2}} ᴀᴛ ᴛʜᴇ sᴜʀғᴀᴄᴇ ᴏғ ᴛʜᴇ ᴇᴀʀᴛʜ

➳ʜ ɪs ᴛʜᴇ ʜᴇɪɢʜᴛ (ɪɴ ᴍᴇᴛʀᴇs)

__________________________________

\sf\purple{Now,\: comming\: to\: the\: problem:-}

ⓖⓘⓥⓔⓝ:-

➳ᴍᴀss ᴏғ ᴛʜᴇ ʙᴏᴅʏ (ᴍ)=20 ᴋɢ

➳ʜᴇɪɢʜᴛ (ʜ)=15ᴍ

Ⓐⓝⓓ,

 {➳g=9.8m/s^{2}}

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\sf\pink{Using\: the\: formula:-}

 ➳{P.E=mgh}

 ➳{P.E=20kg×15m×9.8m/s^{2}}

 {➳P.E=2940kgm^{2}/s^{2}}

 {➳P.E=2940J}

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\sf\orange{Henceforth,}

➳ ᴛʜᴇ ᴘᴏᴛᴇɴᴛɪᴀʟ ᴇɴᴇʀɢʏ(P.E) ᴏғ ᴛʜᴇ ʙᴏᴅʏ ɪs,

 \sf  {\fbox {P.E=2940Joules}}

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\fcolorbox{lime}{black}{\color{lime}{Hope\: it\: works}}

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