A body of mass 20kg is moving with a velocity of 72km/h a force is applied to the body for 25 sec and it attains a velocity of 144km/h what is the force applied?
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F=ma
given, m=20kg a=(u=72×5/18=20 v=144×5/18=40 t=25sec)= (u-v)/t =(40-20)/25= 20/25 =4/5
F=ma
F=20×4/5
F=16N
given, m=20kg a=(u=72×5/18=20 v=144×5/18=40 t=25sec)= (u-v)/t =(40-20)/25= 20/25 =4/5
F=ma
F=20×4/5
F=16N
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