Question

A body of mass 20kg is moving with velocity 10m/s on a horizontal smooth surface collides with a massless spring of spring constant 5 N/m. If the mass stops after the collision, distance of compression of spring is _____

Options:
a) 20m
b) 50m
c) 5m
d) 10m

Give an accurate answer with explanation.
​

Answer 1

Given that,

Mass of body = 20 kg

Velocity = 10 m/s

Spring constant = 5 N/m

If the mass stops after the collision,

We need to calculate the distance compression of spring

Using formula of maximum kinetic energy

$\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2$

$x^2=\dfrac{mv^2}{k}$

Where, m = mass of body

v = velocity

k = spring constant

Put the value into the formula

$x^2=\dfrac{20\times100}{5}$

$x=\sqrt{400}$

$x=20\ m$

Hence, The distance compression of spring is 20 m.

(a) is correct option.

Learn more :

Topic : spring constant

https://brainly.in/question/16042023

Answer 2

Answer:

I need your i can't message. I want to have the answer of these please help.

1. Lets Rome Around ( Identify the figure of speech)

2. Lumber Party ( Identify the figure of speech)

PLEASE MESSAGE ME