Question

a body of mass 20kg rests on a horizontal plane the co efficient of friction between the body and plane is 0.3 finf the work done in moving the body through a distance of 10 meters​

Answer 1

Answer:

0.035

Explanation:

mg−T=ma

⇒30−27=3a

⇒a=1 m/s

2

T−μMg=Ma

⇒27−μ×200=20

⇒μ=

200

7

Answer 2

Answer:

A body of mass 20kg rests on a horizontal plane the coefficient of friction between the body and plane is 0.3. The work done in moving the body through a distance of 10 meters​ will be $588Nm$

Explanation:

• We have the expression for work done as,

        $W = F\times x$     ...(1)

        Where,

        W is the work done to move an object, F is the force applied and x is the distance moved by the object

• Force can be obtained by using the expression,

        $F = \mu mg$        ...(2)

         Where

         $\mu$  - the coefficient of friction

         m - Mass of the object

         g -  acceleration due to gravity.

• In the question, it is given that,

       $m = 20\ kg$           $\mu = 0.3$          $x = 10m$

       We know,

       $g = 9.8m/s^2$

       Substituting these values into equation (2),

      $F = 0.3\times 20\times 9.8 =58.8 N$

      Then using equation(1),

      $W = 58.8\times 10 = 588 \ Nm$