Question

A body of mass 218 kg starts from rest and attains the velocity of 63m/s in 9 seconds. Find its:
(a) acceleration
(b) distance covered in 9 seconds
(c) force

Answer 1

Answer:

In the explanation

Explanation:

M=218kg, V=63 m/s, t= 9s,

a) acceleration= V/t =63/9= 7 m/s^2

b) distance covered = ut+1/2 at^2

u=0 , 1/2 at^2 = 1/2 * 7* 81= 283.5 m

c) Force = M* a = 218 * 7 = 1526 N

Answer 2

✬ Acceleration = 7 m/s² ✬

✬ Distance = 283.5 m ✬

✬ Force = 1526 N ✬

Explanation:

Given:

• Mass of body is 218 kg.
• Body starts from rest.
• Final velocity of body is 63 m/s.
• Time taken is 9 seconds.

To Find:

• Acceleration of the body ,distance covered by the body and force ?

Formula to be used:

• v = u + at (for acceleration)
• s = ut + 1/2at² (for distance)
• f = ma (for force)

Solution: Here we have

• u = 0
• v = 63 m/s
• t = 9 seconds

Substitute the values on first formula for finding acceleration

$\implies{\rm }$ v = u + at

$\implies{\rm }$ 63 = 0 + a × 9

$\implies{\rm }$ 63 = 9a

$\implies{\rm }$ 63/9 = a

$\implies{\rm }$ 7 m/s² = a

So the acceleration is 7 m/s².

[ Let's find distance ]

$\implies{\rm }$ s = ut + 1/2at²

$\implies{\rm }$ s = 0 × 9 + 1/2 × 7 × 9²

$\implies{\rm }$ s = 7/2 × 81

$\implies{\rm }$ s = 567/2

$\implies{\rm }$ s = 283.5 m

Distance covered by body is 283.5 m.

[ And the force will be ]

$\implies{\rm }$ F = m × a

$\implies{\rm }$ F = 218 × 7

$\implies{\rm }$ F = 1526 N

Hence, force is 1526 Newtons.