Question

A body of mass 218 kg starts from rest and attains the velocity of 63m/s in 9
seconds. Find
a) acceleration
(b) distance covered in 9 seconds
(c) force​

Answer 1

Explanation:

is 218 kg.Body starts from rest.Final velocity of body is 63 m/s… ... Find its : (a) acceleration (b) distance covered in 9 seconds (c) ... c) Force = M* a = 218 * 7 = 1526 N

Answer 2

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Acceleration = 7 m/s² ✬

✬ Distance = 283.5 m ✬

✬ Force = 1526 N ✬

Explanation:

Given:

Mass of body is 218 kg.

Body starts from rest.

Final velocity of body is 63 m/s.

Time taken is 9 seconds.

To Find:

Acceleration of the body ,distance covered by the body and force ?

Formula to be used:

v = u + at (for acceleration)

s = ut + 1/2at² (for distance)

f = ma (for force)

Solution: Here we have

u = 0

v = 63 m/s

t = 9 seconds

Substitute the values on first formula for finding acceleration

⟹ v = u + at

⟹ 63 = 0 + a × 9

⟹ 63 = 9a

⟹ 63/9 = a

⟹ 7 m/s² = a

So the acceleration is 7 m/s².

[ Let's find distance ]

⟹ s = ut + 1/2at²

⟹ s = 0 × 9 + 1/2 × 7 × 9²

⟹ s = 7/2 × 81

⟹ s = 567/2

⟹ s = 283.5 m

Distance covered by body is 283.5 m.

[ And the force will be ]

⟹ F = m × a

⟹ F = 218 × 7

⟹ F = 1526 N

Hence, force is 1526 Newtons.