Question

A body of mass 24 kg is attached to a string of length 2m .If the mass is executing vertical circular motion ,the velocity attained by the mass in the lowermost point of the path is : (g=10 m/s2)

Answer 1

Answer:

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Answer 2

Explanation:

Given : u=5m/s a=−g=−10m/s

2

When the string breaks at point P, from there onwards the mass has the free falling motion.

At the maximum height attained, the velocity of the mass is zero i.e v=0m/s

Using v

2

−u

2

=2aS

∴ 0−5

2

=2(−10)h ⟹h=1.25 m

HOPE IT HELPS