Question

A body of mass 25 g has a momentum of 0.40 kg m/s. Find its Kinetic Energy.​

Answer 1

Answer:

$here \: is \: your \: answer$

Explanation:

Given that

m = 25g = 0.025 kg

p = 0.40 kg m/s

Kinetic energy = p²/2m

= (0.40)² / 2(0.025)

= 0.16 / 0.05

3.2J : Answer

By formula 2

K.E. = 1/2 mv²

=m² v² / 2m

= p² / 2 m

K.E. = p²/ 2m = (0.40)² / 2×

25/100

= 3.2 J

You can either use formula 1

or formula 2

hope helpful for you

Answer 2

Answer:

The kinetic energy of the body is 3.2 J.

Explanation:

The mass of the body, m = 25 g = 0.025 Kg

The momentum of the body, P = 0.4 Kgm/s

We know, P = m × v, where 'v' is the velocity of the body.

∴ Velocity of the body, v = P / m

                                         = 0.4 / 0.025

                                      v = 16 m/s

The kinetic energy of the body can be found using the equation,

K.E = (mv²) / 2

     = (0.025 × 16²) / 2

     = (0.025 × 256) / 2

K.E = 3.2 J