Question

A body of mass 25 kilogram is initially moving with a velocity of 30 metre per second a force is applied on it for 5 second which change its velocity to 40 metre per second calculate the rate of change of momentum and acceleration produced in the body and force applied on the body

Answer 1

here's ur answer...hope it helps

Answer 2

Answer:

Rate of change of momentum = 50 N

Acceleration of the body = $2\ m/s^2$

Force on the body = 50 N

Explanation:

Given:

• m = mass of the body = 25 kg
• u = initial velocity of the body = 30 m/s
• v = final velocity of the body = 40 m/s
• t = time interval = 5 s

Assume:

• a = acceleration of the body
• F = force of on the body
• $\Delta P$ = change in momentum of the body

Rate of change in momentum = $\dfrac{\Delta P}{t}=\dfrac{m(v-u)}{t}=\dfrac{25(40-30)}{5} = 50\ N$

According to the Newton's second law, the rate of change of momentum is the force applied on the body.

$\therefore F = \dfrac{\Delta P}{t}=50\ N$

Force on the body = 50 N

Acceleration of the body = $\dfrac{F}{m}=\dfrac{50}{25} = 2\ m/s^2$