a body of mass 2g initially at rest moves under the action of an applied horizontal force of 7N on a table. find the acceleration produced by the applied force.
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Answer:
3500 m/s²
Explanation:
First, we need to convert 2 g to its S.I unit, i.e, kg.
1 g = 1/1000 kg
2 g = 2/1000 kg = 0.002 kg
Force = Mass * Acceleration
7 N = 0.002 * Acceleration
Acceleration = 7/0.002
= 3500 m/s²
Hence, the body accelerates at a rate of 3500 m/s² when a force of 7N is applied on it.
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