Question

a body of mass 2Kagist rest .what should be magnitude
force applied such that
it travels a distance
of 100m in 5 sec . also
find it speec at the end of 5sec​

Answer 1

Answer:

Force=16N         ;       Velocity=40m/s

Explanation:

The body of mass 2kg is at rest. After applying a force F, it travels a distance of 100m in 5s

From Equations of Motion, we know that

s=ut+1/2at²

Here,s=distance=100m

        u=initial velocity=0

        t=time taken=5s

        a=?

Putting these values in the formula,

100=0×5 + a/2×5×5

100=25a/2

 25a=200

     a=8 m/s²

So, the acceleration is 8m/s²

Also, by equations of motion.

v=u+at

Here,v=final velocity=?

        u=initial velocity=0

        a=acceleration=8m/s²

        t=time taken=5s

Putting these values in formula,

v=0+ 8×5

v=40m/s

So, the velocity is 40m/s at the end of 5s

From Newton's Second Law of Motion, we know that

F=ma

Here,F=force=?

        m=mass=2kg

        a=acceleration=8m/s²

Putting these values in formula,

F=ma

F=2×8

F=16N

So, force applied is 16 newtons.

HOPE IT HELPS