Question

A body of mass 2Kg changes its position from (1, 1 ,1)m to (2,3.4)m due to application of

(2i+3j+k)N of force. Calculate the amount of work done.?​

Answer 1

Answer:

11joule

Explanation:

work done=force×displacement

net displacement=final -initial

=(2-1)i+(3-1)j+(4-1)k=1i+2j+3k

work=(2i+3j+k).(1i+2j+3k)

work=2+6+3=11

Answer 2

Answer:

11 joules

Explanation:

its used by the formula