Question

a body of mass 2kg falls from rest what will be its k.e. during the fall at the end 2 seconds .

Answer 1

g = 9.8m/s ,
m = 2 kg
t = 2 seconds
u = 0
v = ?
v = u + gt
  = 0 + 9.8 *2 = 19.6 m/s
K.E.=?
K.E.= $\frac{1}{2} mv^2$
       = $\frac{1}{2} * 2 *(19.6 )^2$
       = 384.16 J 

Answer 2

please see the attcahment.