A body of mass 2kg is acted upon by two forces each of magnitude 1N making an angle of 60 degrees with each other . The net acceleration of the body is
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A= F1 = 1 N
B= F2 = 1 N
θ = angle between the 2 forces = 60°
Cos(60) = 1/2
Now Resultant force = √[A^2 + B^2 + 2A.B.Cos(θ)]
=√ (A^2 + B^2) = √3 N
F = √3 N
m = 2 kg
a = F /m = (√3)/2 m/s^2
direction : tan^-1(√3 / 1) with 1N force. or tan^-1(√3) or 60° with =1N force.
i hope it will help you
regards
A= F1 = 1 N
B= F2 = 1 N
θ = angle between the 2 forces = 60°
Cos(60) = 1/2
Now Resultant force = √[A^2 + B^2 + 2A.B.Cos(θ)]
=√ (A^2 + B^2) = √3 N
F = √3 N
m = 2 kg
a = F /m = (√3)/2 m/s^2
direction : tan^-1(√3 / 1) with 1N force. or tan^-1(√3) or 60° with =1N force.
i hope it will help you
regards
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