Question

a body of mass 2kg is being rotated in a circle by 0.5m long string,the work done by centripetal force is?
a.10J
b.zero
c.5J
d.1J​​

Answer 1

Answer:

$given$

$m = 2kg$

$r = 0.5m$

$v = 3m {s}^ - 1{}$

$therefore$

$fc = \frac{m {v}^{2} }{r}$

$= \frac{2 \times {0.3}^{2} }{0.5}$

$= 0.36n$

Explanation:

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Answer 2

Answer:

The work done by centripetal force on a circular path is zero.e.option(b).

Explanation:

The work done is given as,

$W=F.s=Fscos\theta$       (1)

Where,

W=work done

F=force

s=displacement

In the case of a circular motion the work done, the component of force is not along the direction of displacement they are perpendicular to each other and cos90° is zero, at each and every point on the circular track, and therefore the component of force along the direction of displacement will always be zero in case of a body moving along a circle.

Hence, the work done by centripetal force on a circular path is zero.e.option(b).