Question

A body of mass 2kg is initially at rest. A constant force of 5 N acts on it for 10 seconds. What is the average power of the force?

Answer 1

F - Force

t - time

w - work

p - power

a - acceleration

F = ma => a = F/m = 5/2 = 2.5 m/s2

u(intial velocity ) =0

using, s= ut + 1/2 at2

s = 1/2 * 2.5 * 100 = 125 m



W(Work ) = Fs = 5*125 = 625 Joules

P(Power ) = W/t = 625/10 = 62.5 Joules/second = 62.5 Watt

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Answer 2

Given -

                 M = 2 kg

                 F = 5 N

                 T = 10 sec

In this question where,

F = Force

t - time

w - work

 p - power

 a - acceleration

  Step -1

                F = ma

                  a = F/m

                  a = 5/2

                  a = 2.5 m/s2

Step-2

initial velocity  (u)  =0

Using second law of motion -

                       $s= ut + 1/2 at^{2}$

                    $s = u * 0 + 1/2 * 2.5 * 100 \\ s = 0 + 125\\s = 125$

Step - 3

              work (w) = F * s

               w= 5 * 125 = 625 Joules

                  Power ( p) = W/t

                     p = 625/10
                     p= 62.5 Joules/second = 62.5 Watt

so, the average power p = 62.5 watt

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