A body of mass 2kg is kept at rest.A constant force if 6N starts acting on it find the time taken by the body to move through a distance of 54km
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1
Explanation:
here, initial veloctiy(u)= 0
Force acting on it(F)=12N
mass of the body(m)=2kg
displacement of the body(s)=12m
time taken by the body(t)=?
we know,
F=ma
a=F/m=6m/s^2
We know,
s= ut + 1/2at^2
12=1/2×6×t² (as u=0)
t=2 (as t can't be negative)
Answered by
0
Answer:
The time taken is t = 2s. We have F = 6N, m = 2kg, s = 24m and u = 0m/s. From F = ma, on substituting the given values for F and m, we get a = 6m/s². at², we substitute for s, u and a, to get t² = 4 ⇒ t = 2s (-2 is neglected since time cannot be negative).
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