Question

a body of mass 2kg is moving along north-east direction with speed √2 m/s. A force 0.2N is applied on the body due west for 10 seconds. The velocity of the body is?

Answer 1

The component of ‘u’ along X and Y are,

ux = v cos45 = u/√2 = √2/√2 = 1 m/s

uy = v sin45 = u/√2 = √2/√2 = 1 m/s

The X component is influenced by the force along West or negative X.

Force along X is -0.2 N

Mass of the body = 2 kg

Acceleration along X is, a = F/m = -0.1 m/s2

Change in velocity along X in 10 s is,

vx = ux + at

=> vx = 1 + (-0.1)(10) = 0

So, the velocity after 10 sec is only the component along Y or North, which is 1 m/s towards north.



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