Question

A body of mass 2kg is moving along positive X-axis direction with velocity of 5m/s.Now a force of 10â2N is applied at an angle of 45° with X-axis.Its velocity after 3s is

Answer 1

Force along x direction = F cos (45)
100 N = m×a×.707
a = 50×1.414 =70.70 m/s^2
(v-u)/t = 70.70
(v-5)/3 = 70.70
v=217.1m/s

Answer 2

Answer:

Explanation:

I think and is 25ms-1