A body of mass 2kg is moving in a verticle of radius 2m the work done when it moves from the lowest point to highest point is
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.⏩⏩hello mate here is ur ans
given: m = 2kg
h = 2m
then ,,
WKT, W= P.E = mgh= 2× 9.8×2= 39.2 joules
given: m = 2kg
h = 2m
then ,,
WKT, W= P.E = mgh= 2× 9.8×2= 39.2 joules
Answered by
1
first of all to reach the highest point, initial velocity required is
by applying work energy theorem,
work done by all the forces= change in K. E
W = 1/2mv^2 - 1/2mu^2
at topmost point velocity of the body will be
W = 1/2 × 2 × (gr) -[1/2 ×2 × (5gr)]
W= (10×2) - (5×10×2)
= 20- 100
= 80 J
by applying work energy theorem,
work done by all the forces= change in K. E
W = 1/2mv^2 - 1/2mu^2
at topmost point velocity of the body will be
W = 1/2 × 2 × (gr) -[1/2 ×2 × (5gr)]
W= (10×2) - (5×10×2)
= 20- 100
= 80 J
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