A body of mass 2kg is moving with a velocity 8 m/s on a smooth surface .If it is to be brought to rest in 4sec then the force to be applied is
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Answered by
3
v=u+at
0=8+4a
a=-2m/s^2
F=ma
=2×2
=4 N
Answered by
0
Answer:
4N=F
Explanation:
v=u+at
0=8+[-a. 4]
-8=-a. 4
a=2
F=m.a
F=2.2
F=4N
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