A body of mass 2kg is moving with velocity 8m/s on smooth surface if it is to be brought to rest 4 seconds then the force to be appiled is
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Answer:
v= u+ at
0 = 8 + a×4
a= -8/4
a= -2m/s^2
hence, F= ma
= 2× -2
= -4 N.
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