A body of mass 2kg is projected vertically up with a velocity of 100m/s . If it raises to a height of 400m,the energy utilizes to overcome friction is (g=10m/s)
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Given:-
- Mass of the body ,m = 2kg
- Initial velocity ,u = 100m/s
- Height raises , h = 400m
- Acceleration due to gravity ,g = 10m/s²
To Find:-
- Energy utilizes to overcome friction .
Solution:-
As we know that the energy of body because of its position or shape is called its Potential Energy.
Mathematical term of Potential Energy
→ P.E = mgh
Substitute the value we get
→ P.E = 2×10×100
→ P.E = 20×100
→ P.E = 2000 J
Now Converting the Joules into Kilojoules
1 Kilojoule = 1000 Joules
∴ 2000 J = 2000/1000kj = 2kj
∴ The energy utilities to overcome the friction is 2 Kilojoule.
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Given :-
- Mass of the body (m) = 2kg
- Initial velocity of the body (u) = 100m/s
- Height (h) = 400 metres
- Acceleration due to gravity (g) = 10m/s2
To Find:-
- The energy utilised by the body to overcome friction
Solution :-
- We already know that the energy due to to its state of position or shape is potential energy (p)
- Mathematically Potential Energy p = mgh
Lets substitute the value of m, g and h to the equation we get
- P = 2*10*100
- Potential energy = 2000J
Convert Jolue - kilo Jule
1 KJ = 1000J
- So, 2000J = 2000/1000 = 2 Kilo Jule
Hence the energy required to overcome friction = 2Kilo Jules
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