a body of mass 2kg is projected vertically up with velocity 5ms the work done on the body by gravitational force before it is brought to rest momentarily is
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Answer:
work done (w)= mass X acceleration due to gravity X height
(or) w=mgh
Explanation:
velocity become zero at maximum height , so
maximum height attained Hmax = (initial velocity)²/2 x acceleration due to gravity
or. Hmax = u²/2g
Hmax= (5)²/2x10
Hmax= 25/20
Hmax= 1.25m
work done (w)= mgh
w = 2 x 10 X 1.25
w = 25
work done = 25 joules
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