Question

a body of mass 2kg is projected vertically up with velocity 5ms the work done on the body by gravitational force before it is brought to rest momentarily is​

Answer 1

Answer:

work done (w)= mass X acceleration due to gravity X height

(or) w=mgh

Explanation:

velocity become zero at maximum height , so

maximum height attained Hmax = (initial velocity)²/2 x acceleration due to gravity

or. Hmax = u²/2g

Hmax= (5)²/2x10

Hmax= 25/20

Hmax= 1.25m

work done (w)= mgh

w = 2 x 10 X 1.25

w = 25

work done = 25 joules