Question

A body of mass 2kg is released at the top of smooth inclined plane having inclination 30degree. it takes 3sec to reach the bottom. if the angle of inclination is doubled what will be time taken by ball to reach bottom

Answer 1

Answer:

1.5 second ...................

Answer 2

Concept:

• The motion of an object on an inclined surface

Given:

• Mass of the body m = 2kg
• The angle of initial inclination α = 30°
• Time taken in first case t1 = 3s
• The angle of final inclination β = 60°

Find:

• The time taken by the ball to reach the bottom when the angle of inclination has doubled

Solution

In the first case,

s = 0 +1/2g sin α t^2

s = 0.5*9.8* sin30° * 3^2

s = 22.05m

In the second case, the distance covered is the same,

s = 0 +1/2g sin β t^2

22.05 = 0.5*9.8* sin60° * t^2

t = 2.28s

It takes 2.28 seconds for the ball to reach the bottom when the angle of inclination has doubled.

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