a body of mass 2kg is thrown up vertically with Kinetic energy of 490J. If g=9.8m/s the height at which the Kinetic energy of the body becomes half of the original value is
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energy conservation
K1-K2 =mgh
490-490/2=2×9.8×h
490-245=19.6h
245=19.6h
h =245/19.6
h =12.5 m
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K1-K2 =mgh
490-490/2=2×9.8×h
490-245=19.6h
245=19.6h
h =245/19.6
h =12.5 m
Mark it as brainliest
deepa63:
thnx
sorry I made a mistake. I didn't see that the kinetic energy was halved.
thnx for brainliest
it's all right
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