Question

a body of mass 2kg is thrown up with a speed of 25m/s.find its maximum potential energy

Answer 1

Explanation:

Potential energy =mgh

Answer 2

Explanation:

P.E = mgh

To Find h

V^2 - U^2 = 2as

v=0, u= 25, a = -10, s= h

0 - 625 = -2×10 × h

So, h= 625/ 20 meter

P.E = mgh = 2 × 10 × 625/20 = 625 joules...