A body of mass 2kg is thrown upward with initial velocity 20m/s. After 2 second it's kinetic energy will be? (g=10m/s^2)
My book is showing the answer as zero but I think the answer should be 400 J. Pls help
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m= 2 kg
u = 20 m/s
g = - 10 m/s2
g=v-u/t
-10=v-20/2
-20=v -20
hence v=0
KE= 1/2 mv2
=1/2 x2 x v square
= 1x 0 square
=0
Hence your book is correct try rechecking yours
u = 20 m/s
g = - 10 m/s2
g=v-u/t
-10=v-20/2
-20=v -20
hence v=0
KE= 1/2 mv2
=1/2 x2 x v square
= 1x 0 square
=0
Hence your book is correct try rechecking yours
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