A body of mass 2kg is thrown vertically upward with an initial velocity of 20m/s . What will be its potential energy at the end of 2s plz tell me fast tomorrow is my exam
Answers
Answered by
9
Hi there!
Mass of the body, m = 2 kg
Initial velocity, u = 20 m/s
Time taken, t = 2 s
Acceleration due to gravity, g = -10 m/s²
Height covered by the body is given by 2nd Eqn. of motion.
That is,
s = ut + 1/2 × gt²
= 20 × 2 - 1/2 × 10 × (2)²
= 40 - 20
= 20 m
Tnerefore,
P.E. of the body after 2 s = mgh
= 2 × 10 × 20 J
= 400 J
[ Thank you! for asking the question. ]
Hope it helps!
Mass of the body, m = 2 kg
Initial velocity, u = 20 m/s
Time taken, t = 2 s
Acceleration due to gravity, g = -10 m/s²
Height covered by the body is given by 2nd Eqn. of motion.
That is,
s = ut + 1/2 × gt²
= 20 × 2 - 1/2 × 10 × (2)²
= 40 - 20
= 20 m
Tnerefore,
P.E. of the body after 2 s = mgh
= 2 × 10 × 20 J
= 400 J
[ Thank you! for asking the question. ]
Hope it helps!
Answered by
3
Answer:
400 J
Explanation:
hello!!
the equation to find the potential energy is mgh
it is given
m=2 kg u=20 m/s t=2sec
we know that g= 10 m/s square
but we don't know what h is and we need its value to find the answer. there fore we use the equation s=ut+1/2 at2
but here the gravitation is accelerated. so we rewrite the equation as
s= ut+1/2 gt2
substitute the values, and you get
s=20*2+1/2*10*2*2
and u get the value of s as 20 m.
now we can find the potential energy by substituting the values.
P.E= 2*10*20
therefore we get the value as 400 J
hope this answer was helpful
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