a body of mass 2kg moving on a horizontal surface with an intial velocity 4m/s on a friction less horizontal table.Force required to keep the body moving with same velocity is:
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15
m=2kg
u=4m/s
v=4m/s (required to keep body moving with same velocity)
let's suppose time = t
so, a = (v-u)/t = (4-4)/t = 0/t = 0m/s²
so, f= ma = 2(0) = 0N
according to Newton's first law of motion
a body will continue to be straight motion or in a state of rest until an external force is applied on it , so in this case No force is required to keep body moving with same velocity
hope this helps
u=4m/s
v=4m/s (required to keep body moving with same velocity)
let's suppose time = t
so, a = (v-u)/t = (4-4)/t = 0/t = 0m/s²
so, f= ma = 2(0) = 0N
according to Newton's first law of motion
a body will continue to be straight motion or in a state of rest until an external force is applied on it , so in this case No force is required to keep body moving with same velocity
hope this helps
Answered by
9
mass (m) = 2kg
initial velocity (u) = 4m/s
Force required to keep the body in same velocity is F = m x a
No change in velocity means zero acceleration
so F = m x a
F = 2 x 0
F = 0 N
also , F = dp/dt = [mv-mu]/t
if there is no change in velocity then u = v
then mv - mv = 0
F = 0/t = 0 N
initial velocity (u) = 4m/s
Force required to keep the body in same velocity is F = m x a
No change in velocity means zero acceleration
so F = m x a
F = 2 x 0
F = 0 N
also , F = dp/dt = [mv-mu]/t
if there is no change in velocity then u = v
then mv - mv = 0
F = 0/t = 0 N
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