A body of mass 2kg moving on a horizontal surface with an initial velocity of 4m/s comes to rest after 2sec if one wants to keep this body moving on the same surface with an a velocity of 4 m/s the force required is.
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We have,v=u+at
or a=v-u/t
In this question the acceleration provided to the body=(0-4)/2=-2
De acceleration=2
The force which provided the de-acceleration,F=ma=2x2=4N
Now this force is to be opposed ,hence a force of 4N is required to keep the body moving with velocity of 4m/s.
I hope this will help you
or a=v-u/t
In this question the acceleration provided to the body=(0-4)/2=-2
De acceleration=2
The force which provided the de-acceleration,F=ma=2x2=4N
Now this force is to be opposed ,hence a force of 4N is required to keep the body moving with velocity of 4m/s.
I hope this will help you
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