Question

A body of mass 2kg moving with a linear velocity 10m/s then the force that is to be applied to stop it in 2 sec is

Answer 1

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Solution :-

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$a = \frac{v - u}{t} \\ a = \frac{10 - 0}{2} \\ a = 5 \: m {s}^{ - 2} \\ \\ f = ma \\ f = 2 \times 5 = 10 \: newton \:$

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Answer 2

solution-

mass of body =2kg

initial velocity=10m/s

final velocity =o

Time Taken=2sec

then

FORCE=mass×accleration

so

a=v-u÷t

a=0-10÷2

a=-5m/s^2

therefore

f=ma

f=2×-5

f=-10N

hence force is 10N

hope it will help you

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