Question

A body of mass 2kg moving with a velocity of 10m/s is brought to rest in 5 seconds. Calculate the stopping force applied.​

Answer 1

Answer:

don't know it's also my doubt plz explain me

Answer 2

Answer:

A→B

u = 4m/s v=0 t=2sec a=?

v=u+at

0=4+a(2)

a=−2m/s

2

so,

force = ma

=2×2=4N