Question

a body of mass 2kg of is on a table keeping it's surface of area 100cm2 on the table calculate the thrust and pressure exerted by body on the table(g=9.8m/s2)​

Answer 1

Given

• Mass = 2 kg
• Surface Area = 100 cm²
• Gravitational Acceleration = 9.8 m/s²

To Find

• Pressure applied and the force applied

Solution

● Pressure = Force/Area

● F = ma

✭ Converting Units :

• Area = 100 cm² = 100/1000 = 0.1 m²

✭ Force Applied :

→ F = ma

→ F = 2 × 9.8

→ F = 19.6 N

✭ Pressure Applied :

→ Pressure = Force/Area

→ Pressure = 19.6/0.1

→ Pressure = 196 Pa

• And the Thrust is equal to he force applied which is equal to 19.6 N

Answer 2

Answer:-

$\small \bf \underline{Given:}$

★★Mass of the body = 2kg

★★Surface area taken by the body = 100cm²$\small \bf = \frac{100}{1000} = 0.1 {m}^{2}$

★★Velocity = 9.8m/s²

$\small \bf \underline{To \: find:}$

We need to find the thrust and pressure exerted on the table by the body

$\small \bf \underline{Solution:}$

»Thrust exerted by the body on the table:-

Thrust exerted by the body on the table = Mass × Velocity

Thrust exerted by the body on the table = 2 × 9.8

Thrust exerted by the body on the table = 19.6

»Pressure exerted by the body on the table:-

$\small \bf \: Pressure \: exerted \: by \: the \: body \: on \: the \: table = \\ \bf \frac{force}{area}$

$\small \bf \ \: Pressure \: exerted \: by \: the \: body \: on \: the \: table = \\ \bf \frac{19.6}{0.1}$

Pressure exerted by the body on the table = 196Pa

Answer:-

• Thrust exerted by the body on the table = 19.6
• Pressure exerted by the body on the table = 196Pa

@BengaliBeauty

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