Question

a body of mass 2kg providing up has potential energy 400J and kinetic energy 580J at a point P in its path. the maximum height reached by the body is (g=10m/s^2)

Answer 1

in its maximum point all the energy should be in the form of potential energy

therefore the potential energy in the maximum point = 400+580=980J

potential energy = MGH

M=2kg
g=10

980= 2×10×H
H=49 meter

Answer 2

The maximum height reached by the body is $49m.$

Step by step explanation:

Given data:

mass of the body$=2kg$

potential energy(P.E)$=400J$

Kinetic energy(K.E)$=580J$

gravity(g)$=10m/s^{2}$

To find:

We must find the maximum height reached by the body.

Formula to be used:

$mgh=P.E+K.E$

where:

$m=$mass

g$=$gravity

h$=$height

P.E$=$potential energy

$K.E=$Kinetic energy

Solution:

At maximum height, $mgh=P.E+K.E$

$2$×$10$×$h$=$400+580$

$20h=980$

$h=\frac{980}{20}$

$h=49m$

The maximum height reached by the body is $49m$

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