Question

A body of mass 2kg starts from rest when two forces of 2N and 4N acts parallel on a body for 4 sec, find the work performed by the body?

Answer 1

Answer: The work performed by the body is 144 J.

Explanation:

Given that,

Initial velocity u = 0

Mass of the body m = 2 kg

Time t = 4 sec

When two forces are acting parallel on a body .

So, total force F = 2 N+4 N = 6 N

Using newton's second law

The acceleration is

$F = ma$

$6N = 2kg\times a$

$a = 3 m/s^{2}$

Now, using equation of motion

$s = ut+\dfrac{1}{2}at^{2}$

$s = 24m$

Now, the work done is

$W = f\cdot s$

$W = 6N\times 24m$

$W = 144 J$

Hence, the work performed by the body is 144 J.