Question

a body of mass 2kg travelling with a velocity 4m/s strikes on another body of mass 10kg coming in the opposite direction with a velocity of 6m/s after collision the velocity of the first body gets reduced to 0.5m/s. Determine the velocity of the second body​

Answer 1

Explanation:

Let their velocities after the collision be v

1

and v

2

. As we know for elastic collision.

Relative velocity of approach = relative velocity of separation

10−4=v

2

−v

1

⇒6=v

2

−v

1

⇒v

1

=v

2

−6

Applying conservation of momentum,

10×10+5×4=10v

1

+5v

2

120=10v

1

+5v

2

120=10(v

2

−6)+5v

2

=15v

2

−60

15v

2

=180⇒v

2

=12cm/sec

v

1

=6cm/sec