Question

A body of mass 3.5 kg displaces 1000 cm³ of water when dully immersed inside it. Calculate. Volume of the body ( ii) upthrust on body and the apparent weight of body in water

Answer 1

Volume of water displaced = Volume of the body 
Therefore, volume of body = 1000cm^3
Upthrust = Volume of water displaced * density of water * g
  = 1000cm^3 * 1g/cm^3 * g 
  = 1000gf
Apparent weight = Weight in air - Upthrust = 3.5kgf - 1.0kgf = 2.5kgf

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Answer 2

Answer:

1:-Volume of the body = Volume of the water displaced by it......(Archimedes' Principle)

2:-Therefore, Volume of the body is 1000cm^3.

3:-Now , Upthrust = Volume of the body*Density of water*g

4:-Therefore, Upthrust = 1000gf or 1.00kgf

5:-Now, the apparent weight is :- Real weight - Upthrust.......:-(3.5-1.0)=2.5kgff

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