Question

A body of mass 3.6 kg is accelerated uniformly at 0.2ms-2 from rest the magnitude of force acting on it is​

Answer 1

Answer:

0.72N

Explanation:

mass = 3.6kg

acceleration = 0.2m/s^2

force = mass × acceleration

force = 3.6 × 0.2

force = 0.72N

Answer 2

Answer:

Magnitude of force applied on body is 0.72 N

Explanation:

• When a force, F is applied on a body of mass m, it produces an acceleration, a.
• Mathematically, F = ma.
• S.I. unit of Force is Newton (Kg m/sec²).
• If a force produces an acceleration of 1 m/sec² in a body of mass 1 kg then force is said to be of 1 Newton.

Given that :

• mass of body, m = 3.6 Kg
• Acceleration of body, a = 0.2 m/sec²

Solution :

• The force acting on the body is

$F = ma \\ F = 3.6 \times 0.2 \\ F = 0.72 \: N$

• Force applied on body is 0.72 Newton.