A body of mass 3 kg at rest is acted on by a force and the body moves through a distance 20 m in 5 s. force on the body is
Answers
Answered by
2
m=3kg
s=20m
u=0
t=5s
By using s = ut + 1/2at^2
We get accelaration as 8/5 m/s^2
And f = ma = 3*8/5 = 24/5N
s=20m
u=0
t=5s
By using s = ut + 1/2at^2
We get accelaration as 8/5 m/s^2
And f = ma = 3*8/5 = 24/5N
Similar questions