Question

a body of mass 3 kg is moving along a straight line with a velocity of 24 m/s. when it is at a point p , a force of 9 N acts on a body in a direction opposite to its motion. the time after which it will be at p

Answer 1

when it is at point 'p' a force of 9N acts on it in opposite direction ..
due to force of 9N acts on opposite direction it produces retardation to the body...
so,,,,
initial velocity at p = 24 m/s
acceletation = -force/mass
= 9/3 =3m/s^2
so find time taken to stop...
put final velovity=0
a= -3m/s^2
u=24m/s
applying....v = u+at
o=24 - 3t
3t= 24
t=24/3 =8 sec.
so time taken to stop is 8 sec
then, time taken to reach again at point p = 2×8= 16 second..ans..

Answer 2

Answer:

Explanation:

when it is at point 'p' a force of 9N acts on it in opposite direction ..

due to force of 9N acts on opposite direction it produces retardation to the body...

so,,,,

initial velocity at p = 24 m/s

acceletation = -force/mass

= 9/3 =3m/s^2

so find time taken to stop...

put final velovity=0

a= -3m/s^2

u=24m/s

applying....v = u+at

o=24 - 3t

3t= 24

t=24/3 =8 sec.

so time taken to stop is 8 sec

then, time taken to reach again at point p = 2×8= 16 second..ans..

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